Math, asked by Swatibhura, 4 months ago


7)A bag contains 5 red balls and 3 green balls. Find the
probability of getting a ball selected at random -
(a) is a red ball
(b) is not a red ball.

Answers

Answered by anuraggupta8938
1

Answer:

(a) 5/8

(b) 3/8

Step-by-step explanation:

(a) in a bag there are 5 red balls and 3 green balls

so probability of getting a red ball = total no. of red balls/total no of balls in a bag

=5/8

(b) probability of not getting a red ball=(8-5)/8

=3/8.

Answered by RaoDivya
1

Answer:

a) 5/8.

b) 3/8.

Step-by-step explanation:

a) No. of red balls = 5

Total no. of balls= 8

Probablity = No. of red balls/ Total no. of balls

= 5/8.

b) No. of non red balls= 3

Total no. of balls= 8

Probablity= 3/8.

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