Question

7. A body is allowed to fall from the
top of
a building 200 m high and
at the same time another body is
projected vertically upwards from
the ground with a
velocity of 50m/s.
The two stones will meet above
the ground at a height of (Given
g= 10 min)
(1) 100 m (2) 120 m
(3) 140m (4) 160 m
​

Answer 1

Answer:

(2) 120m

Explanation:

H=200m

t=H/u=200/50=4sec

at the height ‘h’ from the ground

h=H-1/2(gt^2)

h=200–1/2(10*16)

=200–1/2*160

=200-80

=120m

The two stones will meet at at a height of 120m.