7. A box contains 10 green, 7 red, 8 yellow, and 3 blue coloured balls. If a single ball is from the box, find the probability of choosing the following:
(a) A green ball
(b) A red ball
(C) A yellow ball
(d) A blue ball
Answers
Answered by
3
Answer:
P(A green ball) = 10/28 = 5/14
P(red ball)= 7/28 = 1/4
P(yellow ball) = 8/28 = 2/7
P(blue ball)= 3/28
Answered by
2
Answer:
- 5/14
- 1/4
- 8/28
- 3/28
Step-by-step explanation:
total number of balls=10+7+8+3
=28
(1) probability of green ball
=number of green ball/total number of ball
=10/28
=5/14
(2) probability of red ball=7/28
=1/4
(3) probability of yellow ball=8/28
(4)probability of blue ball=3/28
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