Question

7.A bullet of mass 0.04 kg moving with a speed of 90m/s enters a heavy wooden block and is stopped after a distance of 60cm. What is the average force exerted by the block in the bullet?

(pls note.. average force is asked
and not average resistive force )​

Answer 1

Answer:

Explanation:

Given,

m=0.04kg

u=90m/s

v=0m/s

S=60cm

From 3rd equation of motion,

2aS = v^2  − u^2

a = −u^2 / 2S

a = −90×90 /  2×60×10^−2  = −6750m/s^2

 

average force = 0.04 * (90 - 0) / 60 = 0.06

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