7. A bus started its journey from Ramgarh and reached Devgarh in 44 minutes at it's average speed of 50 kmph. If average speed of bus is increased by 5 kmph, how much time will it take to cover the same distance ? (a) 40 min (b) 38 min (c) 36 min (d) 31 min
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Answer:
a) 40 min
Step-by-step explanation:
(44 min = 44/60) = 1/15 hr
Let T denotes the time that the bus will take to cover the same distance at higher average speed.
From above data we get as follows,
T*(50 + 5) = (11/15)*50
or 55*T = 110/3
or T = 2/3 (hr) = (2/3)*60 = 40 (min)
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