Question

7. A can do a piece of work in 9 days.
B can do same piece of work in 10 days.
C can do same piece of work in 15 days.
B and C start working and left after 2 days.
In how many days remaining
work will be finished by A?
A. 4
B. 6
C. 8
D. 10​

Answer 1

Step-by-step explanation:

C). 8

Is ur answer......

Answer 2

In 6 days the remaining work will be finished by A.

Step-by-step explanation:

A can do a piece of work in 9 days.

A can do work in 1 day = $\frac{1}{9}$

B can do same piece of work in 10 days.

B can do same work in 1 day = $\frac{1}{10}$

C can do same piece of work in 15 day.

C can do same work in 1 day = $\frac{1}{15}$

B and C together can do the work = $\frac{1}{10}+\frac{1}{15}$

                                                         = $\frac{3+2}{30}$

                                                         = $\frac{5}{30}$

                                                         = $\frac{1}{6}$

B and C together can finish the work in 6 days. but they left after 2 days.

They completed the part of work = $\frac{2}{6}=\frac{1}{3}$

A can do whole work in 9 days, but 1/3 of the work has been completed by B and C.

Number of days of work completed = $\frac{1}{3}\times 9$ = 3 days

Now A can complete the work in = 9 - 3 = 6 days.

In 6 days the remaining work will be finished by A.

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