Question

7)
A car moving along a straight highway with a speed of 72 km h is brought to a stop
within a distance of 200 m. What is the retardation of the car (assumed uniform)?
11​

Answer 1

Answer:

Answer is -1m/s²

Explanation:

u = 72km/h = 72×5/18 m/s = 20m/s.

v = 0m/s [As it will stop]

s = 200m

Using v²-u²=2as, where a is the retardation of the car

0²-20²=2a(200)

-400 = 400a

a = -400/400

a = -1m/s²

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Answer 2

Explanation:

u = 72 kmph ×5/18 = 20m/s

v²-u² = 2as

-u² = 2as

-(20)²/400 = a

-400/400 = a

a = -1m/s²

r = 1m/s²