Physics, asked by neharajput1234, 1 year ago

7. A car travelling with a velocity of 80 km/h slowed down to 44 km/h in 15 s. The retardation is

Answers

Answered by Anonymous
3

Answer:

retradation = -0.6 m/s²

Explanation:

Given:

Initial velocity(u) = 80 km/h = 22.2 m/s

Final velocity (v) = 44 km/h = 12.22 m/s

time (t) = 15 sec

To Find

retradation (a)

Solution

From the equation of motion

\blue{\boxed{\red{v = u + at}}}

12.22 = 22.22 + a(15)

12.22 - 22.22= 15a

-10 = 15 a

a = -0.6 m/s²

Answered by moksh200518
0

Explanation:

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