Question

7 A car travels 10 min 5 seconds, 20 m in next 10 seconds and 30 m in the last 10seconds
seconds. The avelage speed of motion is
a) 20 m/s
b) 2.2 m/s
c) 30 nas
d) 2.4 m/s​

Answer 1

$\huge{\underline{Given:-}}$

${d_1 = 10m ; t_1 = 5 seconds}$

${d_2 = 20m ; t_1 = 10 seconds}$

${d_1 = 30m ; t_1 = 10 seconds}$

$\huge{\underline{Explanation:-}}$

By the formula of average speed

$average \: speed = \frac{total \: distance \: travelled}{total \: time \: taken}$

Substituting the values.

$average \: speed = \frac{10 + 20 + 30}{10 + 10 + 5}$

$average \: speed = \frac{60}{25}$

$average \: speed = 2.4 \: \frac{m}{s}$

$\boxed{\boxed{average speed = 2.4 m/sec}}$

So,the average speed of the particle is 2.4 m/s.