Question

7. A chord 6 cm long is drawn in a circle with a diameter equal to 10 cm. Find its perpendicular
distance from the centre
(a) 4 cm (6) 7 cm (c) 6 cm
(d) 5 cm​

Answer 1

Answer:

Let the circle be with center O and radius 10 cm. Let there be a chord AB

Draw a perpendicular from O on AB to meet at P. The perpendicular from the center divides the chord in two halves. Given, OP=6cm

Thus, In △OAP, Using Pythagoras theorem

OA2=AP2+OP2

102=AP2+62

AP2=64

AP=8 cm

Thus, AB=2AP=16 cm

Now, new chord CD is drawn with length 8 cm. Draw a perpendicular on CD from O to cut CD at N.

Now, In △ONC

OC2=NC2+ON2

102=42+ON2

ON=84 cm

Answer 2

QUESTION :-

7. A chord 6 cm long is drawn in a circle with a diameter equal to 10 cm. Find its perpendicular

distance from the centre

(a) 4 cm (6) 7 cm (c) 6 cm

(d) 5 cm

ANSWER:-

Your answer is 84cm.

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