Question

7. A circular road runs round a circular garden. If the circumference of outer circle are 110 m and 88 m, find the width of road.​

Answer 1

Answer :-

• The width of the road is 3.5m.

Step-by-step explanation :

To Find :-

• The width of the road

Solution :-

Given,

• Circumference of inner circle = 88m

∴ The radius of the inner circle:

=> 2πr

=> 2 × 22/7 × r = 88m

=> 44/7 × r = 88

=> r = 88 × 7/44

=> r = 616/14

=> r = 14

Therefore, the radius of the inner circle is 14m.

Also given,

• Circumference of the outer circle = 110m

∴ The radius of the outer circle:

=> 2πR

=> 2 × 22/7 × R = 110

=> 44/7 × R = 110

=> R = 110 × 7/44

=> R = 770/44

=> R = 17.5

Therefore, the radius of the outer circle is 17.5m.

Now, According the question,

• The width of the road

=> Radius of outer circle - Radius of inner circle

=> R - r

=> 17.5m - 14m

=> ( 17.5 - 14 ) m

=> 3.5m

Therefore,

• The width of the road is 3.5m.

Answer 2

Correct Question :-

• A circular road runs round a circular garden. If the circumference of outer circle is 110m and Circumference of inner circle is 88 m,then find the width of road.

Given :-

• Circumference of Outer Circle = 110m
• Circumference of Inner Circle = 88m

To Find :-

• The width of the road

Solution :-

➞ Circumference of Outer Circle = 2πr

➞ 110 = 2 × 22/7 × Radius

➞ 110 ÷ 2 = 22/7 × Radius

➞ 55 = 22/7 × Radius

➞ 55 × 7 ÷ 22 = Radius

➞ 385 ÷ 22 = Radius

➞ 17.5m = Radius

So, the Radius of the Outer circle is 17.5m

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➞ Circumference of Inner Circle = 2πr

➞ 88 = 2 × 22/7 × radius

➞ 88 ÷ 2 = 22/7 × radius

➞ 44 = 22/7 × radius

➞ 44 × 7 ÷ 22 = radius

➞ 308 ÷ 22 = radius

➞ 14 m = radius

So, the radius of the Inner circle is 14m

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➞ Width of the Path = Radius - radius

➞ Width of the Path = 17.5 - 14

➞ Width of the Path = 3.5m

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Therefore, The width of the road is 3.5m.

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