Question

7. A displacement of a particle executing a
SHM is y = 5 sin 60 nt. The frequency of
SHM is
(1 Point)
60 π Hz
20π Hz
30 Hz
1/30 Hz​

Answer 1

Question:

A displacement of a particle executing a

SHM is y = 5 sin 60 t. The frequency of

SHM is = ?

Given:

• y = 5 sin 60 t
• Amplitude (A) = 5
• Omega (ω) = 60

Solution:

Frequency of SHM = ω/2π

=> ω/2π

=> 60/2π

=> 30 Hz

Therefore, The frequency of SHM is 30 Hz.