7.A father is 30 years older than his son. In 12 years, the man will be three times as old as his son. Find their
present ages.
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Step-by-step explanation:
Let present age of father=x years
and present age of son=y years
According to 1st condition:
x=30+y
Acc. to 2nd condition:
(x+12)=(y+12)3
x+12=3y+36
x-3y=24
x=24+3y
Substitute the equation in 1st condition,
24+3y=30+y
3y-y=30-24
2y=6
y=3
x=24+3y
x=24+3 (3)
x=24+9
x=33
Present age of father=x=33 years
And present age of son=y=3 years
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