Question

7. A father's age is 3 times the sum of ages of his two sons. Five years later he wil
their ages will be 54 years. What are their present ages
twice the sum of ages of his two sons. Find the present age of the father
8. The digits of a two digit number differ by 7. If the digits are interchanged and
and​

Answer 1

Answer:

son is 11     father is 33

Step-by-step explanation:

right now the ages are

son = x

father = 3x

five years later they are

son = x + 5

father = 3x + 5

the sum of them is equal to 54 so

x + 5 + 3x + 5 = 54

4x + 10 = 54

4x = 44

x = 11

3x = 33