Question

7. A flooring tile has the shape of a parallelogram whose base is 24 m and the corresponding height is 10
m. How many such tiles are required to cover a floor of area 1080 m??
​

Answer 1

Correct Question :-

A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080m²?

Given :-

• Area of floor = 1080m²

• Base of tile = 24cm

• Height of tile = 10cm

To Find :-

• Number of tiles that are required to cover a floor of area 1080m²

Solution :-

Base of parallelogram shape tile = 24cm

Height of parallelogram shape tile = 10cm

Now,

$\huge{\boxed{\pink{{Area}_{(parallelogram)}\:=\:B×H}}}$

Substituting the value in the above formula,

$\mapsto{\color{yellow}{{Area}_{(tile)}\:=\:24cm×10cm}}$

$\huge{\boxed{\mathbb{\orange{{Area}_{(tile)}\:=\:240cm²}}}}$

Now, Since the area of tile is in (cm²) we have to convert it into (m²) . And for converting it we have to divide the number by 10000.

∴ $\mapsto{{Area}_{(tile)}\:=\: \frac{240cm²}{10000}}$

$\mapsto{{Area}_{(tile)}\:=\:0.024m²}$

Now,

Area of floor = 1080m²

Area of a single tile = 0.024m²

$\huge{\boxed{\green{{Number}_{(tiles)}\:=\: \frac{Area\:of\:floor}{Area\:of\:tile}}}}$

$\mapsto{{Number}_{(tiles)}\:=\: \frac{1080m²}{0.024m²}}$

$\mapsto{{Number}_{(tiles)}\:=\: \frac{\cancel{1080m²}}{\cancel{0.024m²}}}$

$\huge{\boxed{\red{{Number}_{(tiles)}\:=\:45000}}}$

∴ The number of tile required to cover the floor is 45,000

Answer 2

Answer:

Area of floor=1080\ m^21080 m

2

To find,

No.of tiles required to cover the floor

=\frac{area\ of\ floor}{area\ of\ 1\ tile}

area of 1 tile

area of floor

Area of tile in the shape =base\ \times heightbase ×height

base=24 cm height=10 cm

Area=24\times1024×10

=240\ cm^2240 cm

2

No.of tiles=\frac{area\ of\ floor}{area\ of\ each\ tile}

area of each tile

area of floor

=\frac{1080\ m^2}{240\ m^2}=

240 m

2

1080 m

2

==1080\times100000\div240\ cm^2=1080×100000÷240 cm

2

=45,000 tiles.