7. A force of 4.0 N acts on a body of mass 2.0 kg for 4.0 s. Assuming the body to be initially at rest, find (a) its velocity when the force stops acting, (b) the distance covered in 10 s after the force starts acting
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f=4N
m=2kg
t=4s
u=0
(i) v=?
v=u+at
=)v=0+2×4
=)v=8 m/s^2
(i) s=?
s=ut+1/2at^2
=)s=0+1/2×2×10×10
=)s=100 m
Hope it helps u.
m=2kg
t=4s
u=0
(i) v=?
v=u+at
=)v=0+2×4
=)v=8 m/s^2
(i) s=?
s=ut+1/2at^2
=)s=0+1/2×2×10×10
=)s=100 m
Hope it helps u.
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