7. A hall has four walls, each measuring 11.5 m x 7.2 m. It has two doors of height
width 1 m. It also has three windows of size 1 m x 0.5 m. Find the cost of white
Answers
Correct Question :-
A hall has four walls, each measuring 11.5 m x 7.2 m. It has two doors of height 2 m width 1 m. It also has three windows of size 1 m x 0.5 m. Find the cost of whitewashing at rate of Rs 65 per meter?
Given :-
Length of the wall = 11.5 m
Breadth of the wall = 7.2 m
Height of the door = 2 m
Width of the door = 1 m
Dimension of the window = 1 m x 0.5 m
To Find :-
The cost of the whitewash.
Analysis :-
At first find the area of the wall and multiply it by 4.
Then find the area of the door and multiply it by 2 and also the area of the windows and multiply it by 3.
Add the area of the doors and the windows and subtract it from the area of wall.
Multiply the cost of whitewashing per meter to the number we got after subtracting.
Solution :-
We know that,
- l = Length
- h = Height
- b = Breadth
By the formula,
Given that,
Length (l) = 11.5 m
Breadth (b) = 7.2 m
Substituting their values,
Area = 11.5 × 7.2
Area = 82.8 m²
Since there are four walls,
82.8 × 4 = 331.2 m²
Therefore, the area of four walls is 331.2 m².
Area of the door = Length × Breadth
Given that,
Length (l) = 2 m
Breadth (b) = 1 m
Substituting them,
Area = 2 × 1 = 2 m²
Since there are 2 doors,
2 × 2 = 4 m²
Area of window = Length × Breadth
Substituting them,
Area = 1 × 0.5 = 0.5 m²
Since there are 3 windows,
0.5 × 3 = 1.5 m²
Now,
Area of whitewashing = 331.2 - (4 + 0.5 + 1.5)
Area = 325.2
Given that, cost of whitewashing per meter = Rs. 65
Therefore,
Cost of whitewashing the hall = Cost per meter × Area of walls
By substituting,
Cost of whitewashing = 65 × 325.2
Cost = Rs. 21138
Therefore, the cost of whitewashing is Rs. 21138.
Answer:
11.5*7.2*4=331.2
2*1*2=4
1*.5*3=1.5
4+1.5=5.5
331.2-5.5=325.7
325.7*65=21170.5