Question

7. A hollow metal pipe is 63 cm long. The inner diameter of cross-section is 4 cm and the outer diameter
4.8 cm. Find the total surface area of the pipe.​

Answer 1

PIPE:

outerSA=2πRh=2xπx2.4 x 63 =302.4πcm2

Inner SA= 2πrh=2πx2x63=252πcm2

2 Base areas=2π(R+ r)(R-r)

= 2π(2.4+2) (2.4-2) = 2πx4.4xo.4

= 8.8πx04=3.52πcm2

TSA = 302.4π +252π +3.52π

=557,92π = 1752cm2

please mark this as brainliest

Answer 2

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Required answer-:

The outer radius is 4.8cm

The height of pipe 63cm

The surface area of pipe is 2πrh

2$\frac{22}{7}$×4.8×63

18×22×4.8=1900.8cm2

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