Physics, asked by sangeetaonline121, 7 months ago

7.(A) if the potential difference between a wire of fixed resistance is doubled, by
how much does the electric power increase (1m)

Answers

Answered by nehaa0704

0

Answer:

I hope you know this well known formula

Power = (Potential difference)^2 / Resistance

P = V^2 / R

For fixed resistance

P ∝ V^2

∴ If Potential difference is doubled then the power increases by 4 units.

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