Question

7. (a) In adjoining figure, RS is diameter of the circle. MNǁRS and ∠MRS=29˙find ∠RNM]

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Answer 1

Answer:

$\huge\blue {\mathfrak{Bonjour Mate!}}$

Join RN and MS.

∴ ∠RMS = 90°

(Angle in a semicircle is a right angle)

∴ ∠RSM = 90° - 29° = 61°

(By angle sum property of triangle RMS)

∴ ∠RNM =180° ∠RSM =180° - 61° = 119°

(pair of opposite angles in a cyclic quadrilateral are supplementary)

Answer 2

Answer:

I don't know the answer,,,,,,,