Question

7. A is twice old as B. Five years ago A was 3 times as old as B. Find their present ages. ​

Answer 1

Answer:

A = 20 years

B = 10 years

Step-by-step explanation:

As per the question,

Let us say the age of B = x

So,

Age of A = 2x

Age of A, 5 years ago = 2x - 5

Age of B, 5 years ago = x - 5

So from the given question we can say that

(2x-5)=3(x-5)

2x-5=3x-15

x=15-5=10

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Answer 2

As per the data given in the question,

We have to determine the present age of A and B.

As, it is given in the question,

• A is twice old as B.
• Five years ago A was 3 times as old as B

Let the present age of B = x years

So, present age of A will be twice as of the age of A $=(2\times x) = 2x\:years$

So, before 5 years,

Age of A, will be $= (2x - 5) \:years$

Age of B will be $(= x - 5)\: years$

As it is given that,

• Five years ago A was 3 times as old as B

So we can rewrite the above expression as,

$(2x-5)=3(x-5)\\2x-5=3x-15\\x=15-5=10\:years$

Hence, present age of A will be $=(2x) = (2\times 10) = 20\: years$

Present age of B will be $=x = 10\: years$