Math, asked by sahukumar093, 5 hours ago

7. A man goes 15 m due west and then 8 m due north. Find the shortest distance from the
starting point.
एक व्यक्ति पश्चिम दिशा में 15 मी. जाता है और पूर्व दिशा में 8 मी. जाता है ज्ञात कीजिये की वह प्रारम्भ
बिदु से काम से काम कितनी दुरी पर है ?
(b) 16
(a) 15
(c)17
(d) 18
De which is the offit rencolo.​

Answers

Answered by archichoudhary25
0

Answer:

17m

Step-by-step explanation:

first the man goes to the west 15 m from point A to point B and then it turns north from point B and walks 8 m to point C. SO, AC = 17 metres.

Answered by varsha212007
0

Answer:

H² = p²+b²

h² =8²+15²

h² = 64 + 225

h² = 289

h = ✓ 289

h = 17

shorter distance from the starting point is = 17m

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