Question

7. A man is 24 years older than his son. In 2 years, his age will be twice the age or his son. Find the ages. ​

Answer 1

Answer:

Step-by-step explanation:

Let the present age of his son be X years.

So, present age of his father = X+24 (as he is 24 years older than his son)

After 2 years, father's age become (X+24+2) years and Son's age will be (X+2).

Now, according to question,

X+24+2 = 2*(X +2)

Or, X = 22 years.

Son's present age = 22 years.

I hope this answernis helpful to you!!

Answer 2

Step-by-step explanation:

let the son present age=x

then man present age=x+24

After 2 years son age =x+2

After 2 years man age=x+24+2

then ATQ

2(x+2)=x+26

2x+4=x+26

2x-x=26-4

x=22

so son age=22years

man age=22+24=46years