Question

7. A man moves on a straight horizontal road with a block
of mass 2 kg in his hand. If he covers a distance of 40 m
with an acceleration of 0.5 m/s?, find the work done by
the man on the block during the motion. all are telling it's formula as w=F.S
then,w=ma.s
but I have doubt where is the angle (thita)i.e W=F.S Cos thita
can anyone explain then I will make him/her brainleist .... please do answer correctly​

Answer 1

Answer:

My friend your are asking your doubt from a correct person. You are right!!! the force which acting on the man will be perpendicular to the distance it covers, that means the angle between force (mg) and distance is 90° which is W=F.Scos(θ=90°) i.e

work=0 but my friend you didn't notice the acceleration which acts on a body. Which therefore according Albert einstein E=mc², if their is certain acceleration some work is done along the path of dispacement therefore, F=ma/E=mc² comparing both we get F=E therfore θ=0° along the path of distance therefore W=maS×1

==>2X0.5X40=40J. If u look carefully you will find that W=S=40. The magnitude is equal.

Explanation:

Here is your answer if u get the concept than mark this as brainliest