Question

7. A merchant has 403 litres, 434 litres and 465
litres of three kinds of oil. If he wants to fill all
kinds of oil in tins of equal volume separately,
then the minimum numbers of tin are
necessary:
(a) 21 (b) 42
(c) 7
(d) 84​

Answer 1

Answer:

b) 42

Step-by-step explanation:

equal volume of oil =31 litres

403 = 31 * 13

434 = 31 * 14 ( 2*7)

465 = 31 * 15 (3*5)

So the answer is 13 + 14 + 15 = 42.

Answer 2

Answer:

25

Step-by-step explanation:

403 => 13*31

434 => 14*31

465 => 15*31

All three oils can be fitted in tin with quantity 31 litres.

So,

403 litres of oil needed 13 tins

434 litres of oil needed 14 tins

465 litres of oil needed 15 tins

Total Number of tins = 13+14+15 = 42