Math, asked by medhini15, 1 month ago

7. A metal sheet of length 2 cm and breadth 44 cm is
rolled to form a hollow pipe of lenght 2 cm. Then the
radius of that pipe is​

Answers

Answered by AQCR
1

Answer:

7 cm

Step-by-step explanation

Circumference formula is 2πr

∴ As, breadth of the sheet has now been rolled to form the cylinder(hollow pipe)'s circumference, the circumference = 44 cm.

∴ 44cm = 2πr.

∴ r = 44cm/2π

∴ (Considering value of π{pi} as 22/7), r = 44cm/(2*22/7)

∴ r = 44/(44/7)

Taking reciprocal,

∴ r = 44 * 7/44

∴ r = 7 cm.

∴ Radius of the pipe = 7 cm

Answered by shubhashreevgujjar3
0

Answer:

i guess u got the answer.....

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