Question

7. A particle is projected from the ground at an angle 'e'
with horizontal with some velocity. For any position
of point 'A'. Show that tan a + tan B=tane, where
'O' is angle of projection.
A(x, h)
in BN
X
MR-X B​

Answer 1

Answer:

Let P be the point at maximum height H. At what height above the point P the ... tan\Theta = (H+x)/(H/2) = \sqrt{abov

max height = range u2sin\Theta/2g = 2u2sin\Thetacos\Theta/g ½ = 2cos\Theta then cos\Theta = ¼ then tan\Theta = \sqrt{15} let height above point .