Question

7 A particle starts from rest and moves in a straight line. If it attains a velocity
20 m/s in 5 minutes, what is its acceleration?
20-0​

Answer 1

Given:-

• Initial velocity ,u = 0m/s

• Final velocity ,v = 20m/s

• Time taken ,t = 5min = 5×60 = 300s

To Find:-

• Acceleration ,a

Solution:-

As we know that acceleration is defined as the rate of change of velocity at per unit time.

• a = v-u/t

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

→ a = 20-0/300

→ a = 20/300

→ a = 2/30

→ a = 0.06 m/s²

Therefore, the acceleration of particles is 0.06m/s².

Answer 2

Answer:

$\huge \tt \: required \: answer$

$\sf \circ \: initial \: velocity(u) = 0m \: per \: sec$

$\sf \circ \: final \: velocity (v)\: = 20 \: m \:per \: sec$

$\sf \circ \: time \: taken \:(t) = 5 \:$

$\huge \bf \: a \: = \frac{v - u}{t}$

Here,

A = Acceleration

V = Final Velocity

U = Initial velocity

T = Time taken

$\sf a \: = \dfrac {20 - 0}{300}$

$\sf \: a \: = \dfrac{20}{300}$

$\sf \:a \: = \dfrac{2}{30}$

$\huge \bf \: a \: = 0.06 \: m {}^{2}$