7.
A particle starts moving from position of rest under a constant acceleration. If it travels a distance x int
sec. The distance it will travel in next t sec will be
(A)2x
(B) 3x
(C) 4x
(D) 5x
Answers
Answered by
0
Answer:
A particle starts from the position of rest under a constant acceleration. It travels a distance x in the first 10 seconds and distance y in the next 20 seconds. Then
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ANSWER
initially velocity is zero, and acceleration is a, so distance covered in 10 sec is x=
2
1
a10
2
=50a
now distance covered in total 30 sec is x+y=
2
1
a30
2
=450a
so y=400a,x=50a
so y=8x
best option is option A
Answered by
0
Explanation:
The energy of one photon is
E=
λ
hc
=
0.57×10
−6
6.626×10
−34
Js×3×10
8
m/s
=3.487×10
−19
J .
25 watt corresponds to 25 J per second.
The number of photons emitted per second is
3.487×10
−19
25
=7.17×10
19
/s.
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