Math, asked by Onkarkharade, 5 months ago


7. A passenger train, running at a speed of 80 km/h leaves a railway station6 hours after a goods train leaves and overtakes it in 4 hours. What is the speed of the goods train?

(A) 32 km/h
(B) 48 km/h
(C) 60 km/h
(D) 50 km/h

TELL WITH METHOD ​

Answers

Answered by s14547aprachi13804
0

Answer:

Also, by the time the train is overtaken, the passenger train should have travelled the same distance as the goods train. It is given that the speed of the passenger train is 80 km/hr and time taken is 4 hours. Therefore, the speed of the good train is 32 km/hr. Hence, the answer is option (a).

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Answered by mayankjangde08
5

Answer:

let speed of goods train is y km/hr.

distance travelled by goods train in 6 hours=6y km.

relative speed =(80-y)km/hr.

since passenger train overtakes goods train in 4 hours. so,6y=4*(80-y)

so, y=32km/hr.80 km/h after 6 hours it had traveled distance 480 km(6*80).

but goods traveled same distance in 4 hours .so speed=distance/time (480/4) =120 km/hour.6 years agoHelpfull: Yes(7) No(9)It is simple problem

Passenger train travel only 4 hours at speed of 80 km/h so total time is 80 * 4 = 320

similarly good train travel 6 hours + 4 hours = 10 hours and distance to cover is 320

simply speed of good train is 320/10 = 32 Answer4 years agoHelpfull: Yes(6) No(1)Passenger train travels for 4 hr

So distance covered by it= 80*4=320km.

Now good train has traveled for (6+4)hrs=10hr

But covered same distance as passenger train.

So speed of good train=(320/10)=32km/hr4 years agoHelpfull: Yes(3) No(0)passenger train travels at a speed of 80km/h after 6 covers 480 kmph

goods cross the distance in 4 hours,so distance in 4 hours=480/4=120kmph4 years agoHelpfull: Yes(2) No(3)Speed of Passenger rain = 80km/h and overtakes goods train in 4 hours

Therefore Distance covered by the Passenger train is = speed * time = 80*4 = 320km

Good Train leave 6 hour before Passenger train hence Time Traveled = 6h

Speed of Good Train = distance/time = 320/6 = 53.3km/h4 years agoHelpfull: Yes(0) No(4)120km/hr

4 years agoHelpfull: Yes(0) No(2)Passenger train travel only 4 hours at speed of 80 km/h so total distance travel is 80 * 4 = 320

let y be the speed of goods train...

And good train travel on that time ( 6 hours + 4 hours) = 10 hours and distance covered is y*10

so speed is 80*4=y*10

320=10y

y= 32 km/h Answer4 years agoHelpfull: Yes(0) No(0)Passenger train travel only 4 hours at speed of 80 km/h so total distance travel is 80 * 4 = 320

let y be the speed of goods train...

And good train travel on that time ( 6 hours + 4 hours) = 10 hours and distance covered is y*10

so speed is 80*4=y*10

320=10y

y= 32 km/h Answer4 years agoHelpfull: Yes(0) No(0)80*4=320km.is the distance traveled to over take goods train.

goods train also travel same distance but in 10h hours

hence speed =320/10=32 km/h3 years

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