Question

7
A person weighing 60 kg in a small boat of
mass 140 kg which is at rest, throws a 5 kg
stone in the horizontal direction with a velocity
of 14 ms. The velocity of the boat
immediately after the throw is ( in m/s)
1) 1.2 2) 0.5 3)0.35 4) 0.65​

Answer 1

Explanation:

Velocity of boat = -0.35 m/s

● Explanation -

Let mp, mb and ms be mass of the person boat and stone respectively.

# Given -

mp = 60 kg

mb = 140 kg

ms = 5 kg

vs = 14 m/s

# Solution -

Initial momentum of the system is -

pi = ms.us + (mp+mb).u

pi = 5×0 + (60+140)×0

pi = 0

Final momentum of the system will be -

pf = ms.vs + (mp+mb).v

pf = 5×14 + (60+140)×v

pf = 70 + 200v

By law of conservation of momentum,

pi = pf

0 = 70 + 200v

v = -70 / 200

v = -0.35 m/s

Therefore, velocity of the boat after throwing stone is 0.35 m/s in opposite direction.

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