Question

7. A picture has 15 cm by 2.5 cm dimensions. A 2.5 cm broad frame is required to cover it. Find
the cost of the frame at * 1.50 per sq. cm.
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Answer 1

Answer:

Hope its helpful

Step-by-step explanation:

Since we have given that

Length of a picture = 15 cm

Width of a picture = 2.5 cm

so, Area of a picture is given by

\begin{gathered}A=Length\times Width\\\\A=15\times 2.5\\\\A=37.5\ cm^2\end{gathered}

A=Length×Width

A=15×2.5

A=37.5 cm

2

As we have that frame 2.5 cm broad is required to cover it.

So, Length of outer part becomes

\begin{gathered}15+2.5+2.5\\\\=20\ cm\end{gathered}

15+2.5+2.5

=20 cm

Width of outer part becomes

\begin{gathered}2.5+2.5+2.5\\\\=7.5\ cm\end{gathered}

2.5+2.5+2.5

=7.5 cm

so, Area of outer part is given by

\begin{gathered}20\times 7.5\\\\=150\ cm^2\end{gathered}

20×7.5

=150 cm

2

So, Area of frame =Area of outer part - Area of picture

\begin{gathered}150-37.5\\\\=112.5\ cm^2\end{gathered}

150−37.5

=112.5 cm

2

Cost of the frame =$1.50 per sq. cm.

So, Total cost becomes

\begin{gathered}112.5\times 1.50\\\\=\$168.75\end{gathered}

112.5×1.50

=$168.75

Hence, Total cost of frame is $168.75.