Question

7. A pole 6m high casts a shadow 2underroot3m long on the
ground. Then the sun's elevation is :??​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

height of pole=6m

length of shadow=2√3m

tan theta=p/b

tan theta =6/2√3

=3/√3

on rationalising it,

3/√3×√3/√3 = √3

tan theta = √3

tan theta =tan 60

on comparing,

theta = 60 degree