Question

7: A pole of length
49 feet broke in the storm. 12 feet is still standing straight in the ground
and the remaining is hinged and touches the ground some distance away. How far is the end
of the pole from the base of pole along the ground?
​

Answer 1

Answer:

since, it is forming a right angled triangle we can use Pythagoras theorem to find BC.

$ac {}^{2} = ab {}^{2} + \ bc {}^{2} \\ bc {}^{2} = ac {}^{2} - ab {}^{2} \\ bc {}^{2} = 37 {}^{2} - 12 {}^{2} \\ bc = \sqrt{1369 - 144 } \\ bc = \sqrt{1225} \\ bc = 35 \: feet$

therefore, the end of the pole from the base of pole along the ground is 35 feet far.

Answer 2

Answer:

hey i know im late but i just did the math and the answer is 45ft not 35 hope this helps

Step-by-step explanation: