Question

7. A proton has a mass 1.67 x 10-27 kg and charge
+1.6 10-19 C. If the proton is accelerated through
a potential difference of million volts, then the
kinetic energy is
​

Answer 1

Answer:

According to the problem the mass of the proton is 1.67 x 10^(-27) kg and the charge of the proton is +1.6 10^(-19) C

At initial state the kinetic energy of the particle is zero

Therefore energy = potential energy = q x v = 1.6 10^(-19) x 1 x 10 ^6 J

After acceleration it has gained kinetic energy

Therefore,

Kinetic energy = qv = 1.6 10^(-19) x 1 x 10 ^6 v = 1.6 x 10^(-13) J

Answer 2

Explanation:

we know that KE = QV

Q = 1.6×10^-19

V = 1×10^6

KE = 1.6×10^-19 × 1 × 10^6

KE = 1.6 × 10^-13

HOPE IT HELPS YOU......

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