Question

7. A room is 5.4m long and 4.5
m wide. Its area is
O a. 122 sq.m
ООО
O b. 24.3 sq.m
O c. 15,4 sq.m
O d.14.6 sq.m​

Answer 1

Answer:

$14.6 {}^{2} m$

Answer

Given :

Length of the floor is 5m

The breadth of the floor is 4m

So, ( applying ar. l×b )

ar. of floor =4m×5m=20m2. Side of the carpet is 3m

So, (applying ar. of sq. =side×side(s))

area of carpet=3m×3m=9m2. 

To find the area of the floor that is not carpeted or (uncarpeted) we will (−) minus the ar. of the floor from ar. of carpet 

area which is not carpeted or( uncarpeted ) =20m2−9m2

=11m2. 

Hence, answer Is 11m2.

Answer 2

Answer:

Given :-

Diameter of the cylinder = 2 m

Height of the cylinder = 3.5 m

To Find :-

LSA

Solution :-

We know that

LSA = 2πrh

qq

At first

⟹ R = D/2

⟹ R = 2/2

⟹ R = 1 m

Now,

Putting value

⟹ LSA = 2 × 22/7 × 1 × 3.5

⟹ LSA = 2 × 22/7 × 1 × 35/10

⟹ LSA = 2 × 22 × 1 × 5/10

⟹ LSA = 44 × 1 × 1/2

⟹ LSA = 44/2

⟹ LSA = 22 m