Question

7. A rope of mass 0.1 kg is connected at the same
height of two opposite walls. It is allowed to
hang under its own weight. At the contact
point between the rope and the wall, the rope
makes an angle 0 = 10° with respect to the
horizontal. The tension in the rope at its
midpoint between the wall is,​

Answer 1

Answer:

2.821 N

Explanation:

Given  A rope of mass 0.1 kg is connected at the same

height of two opposite walls. It is allowed to

hang under its own weight. At the contact

point between the rope and the wall, the rope

makes an angle 0 = 10° with respect to the

horizontal. The tension in the rope at its

midpoint between the wall is,

From the condition of equilibrium , we know that the horizontal components are equal in magnitude and opposite to each other.

Now let T be the tension.

So mg = 2 T sin θ

T = mg / 2 sin 10

T = 0.1 x 9.8 / 2 x 0.1736

             0.98  / 0.347296

So T = 2.821 N

Answer 2

Answer:

2.82 N

Explanation:

here is the step by step explanation. of the answer. before going into it please have a look on the attached pic for better understanding of the question.

Let the tension in each section AB and AC be T. Now, from the condition of equilibrium it is clear that the horizontal components are equal in magnitude and opposite to each other so they cancel out each other. Hence,  

mg=2Tsin10

∴

T=[mg/2sin10]

 =(0.1×9.8)/(2×0.1736)

 =2.82N