Question

7. A scooter moving at a speed of 10 ms - is stopped by applying brakes which produced
acceleration of, 0.5 ms-2. How much distance will be covered by the scooter before it
stops​

Answer 1

Explanation:

u=initial velocity

v=final velocity

a=acceleration

d=distance

U=10m/s,

V=0( it will stop at end so v=0 ) ,

Acceleration={−0.5m/(s^2)}

d=?

V^2 =U^2 +2ad

0=100−2(0.5)d

d=100m