Question

7. A solid cylinder of mass 50 kg and
radius 0.5 m is free to rotate about a
horizontal axis. A cord is wound
around it such that its one end is
free. The tension in the string
required to produce an angular
acceleration of 2 rotation/sec2 in the
cylinder will be -
a) 200 N
b) 157 N
c) 100 N
d) 50 N​

Answer 1

Answer:

D) 157N

Explanation:

Mass of the cylinder m=50kg (Given)

Radius of the cylinder r =0.5m  (Given)

α = 2 rev/s²

Torque by Tension in string = T × R= T × 0.5 = T/2 N-M

= T = Iα = T/2 = Iα

= T/2 = 50 × (0.5)² × 4π/2

T = 157N

Therefore, Tension in the string required to produce an angular acceleration of 2 revolutions s⁻² is 157N.

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