Question

7. A sphere of mass 40 kg is attracted by a second sphere of mass 80 kg with a force equal to 2.46 x 10-6 N when they are placed
30 cm apart. Find the value of G.
(Ans. 6.88x10-11 Nm2 kg-2)​

Answer 1

Answer:

Distance (G)=20cm=0.2m

Mass (M

1

)=40kg Mass (m

2

)=15kg

Force (F)=0.1 milligram wt

=0.1×10

−3

×980 dyne

=98×10

−3

dyne

=98×10

−8

N

=9.8×10

−9

N

F=

R

2

GM

1

M

2

G=

M

1

M

2

Fk

2

=

40×15

9.8×10

−7

×0.2×0.2

=

4×15

98×2×2

×

10×10×10×10

10

−7

=6.5×10

−11

m

2

/kss

2