7. A spinner has 6 sectors, half of which are red and half of which are black. If the radius of the spinner is 3 inches, what is the area of the red sectors?
Answers
Answer:
66/7. Square inches
as the are will be pie r sqare by 2
Given : A spinner has 6 sectors, half of which are red and half of which are black. The radius of the spinner is 3 inches.
To find : The area of the red sectors.
Solution :
We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the area of the red sectors)
Area of the whole spinner :
= π × (radius)²
= 3.14 × (3)²
= 28.26 sq. inches
Number of the red sectors :
= Total sectors ÷ 2
= 6 ÷ 2
= 3
Now,
Area of the 6 sectors = 28.26 sq. inches
Area of the 1 sector = (28.26/6) sq. inches
Area of the 3 sectors = (28.26 × 3)/6 = 14.13 sq. inches
(This will be considered as the final result.)
Hence, the area of the red sectors is 14.13 sq. inches.