7. A stone is thrown vertically up from the top of a tower with a velocity of 5 m/s. It reaches the ground after 8s. Find the height of the tower?
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Let us consider velocity of the stone at the top of the tower is u and the final velocity as v. Since the stone is travelling towards the ground, therefore acceleration is equal to gravity g =9.8m/s² and time is t.
According to one of the kinematic equations
s=ut+1/2at²
Where s is the distance.
s=(5*8)+1/2(9.8*8²)
s=40+1/2(627.2)
s=40+313.6
s=353.6
Therefore the height of the tower is 353.6 metres
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