Math, asked by shazia141076, 10 months ago

7. A takes 6 days less than the time taken by B to finish a piece of work. If both A and B

together can finish it in 4 days, find the time taken by B to finish the work.​

Answers

Answered by meowwww75
0

Hey !

Given,

A takes 6 days less than the time taken by B to complete a piece of work.

Let the time taken by B to finish the work be x

=> time taken by A to finish the same work = x-6.

time taken by both working together = 4 days

In one day, calculate the part of work done.

Work done by A = 1/x

Work done by B = 1/(x-6)

Work done by both A and B, working together = 1/4.

Since, work done by both A and B is sum of their individual work done

=> 1/x + 1/(x-6) = 1/4

=> x-6/x(x-6) + x/x(x-6) = 1/4

=> (x-6+x)/x(x-6) = 1/4

=> 4(2x-6) = x²-6x

=> x²-14x + 24 = 0

=> x(x-2)-12(x-2) = 0

=> x = 12 and 2

If time taken by B is 2 days, A takes 2-6 = -4 (daysNon existence)

•°• If time taken by B is 12 days , A takes 12-6 = 6 days

•°• B takes 12 days to finish the work.

meowwww xD

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