Question

7.) A taxi is travelling at 15 m/s. Its driver accelerates with
acceleration 3 m/s2 for 4 s. What is its new velocity?​

Answer 1

Answer:

The new velocity of the taxi is 27 m/s.

Explanation:

Taxi is travelling at = 15 m/s

Acceleration of the taxi = 3 m/s²

Time = 4 seconds

New velocity = ??

$\bigstar \: \boxed{\sf{v = u + at}}$

• u = 15 m/s
• a = 3 m/s²
• t = 4 seconds

$\sf{\longrightarrow} \: v = 15 + (3)(4)$

$\sf{\longrightarrow} \: v = 15 + 12$

$\sf{\longrightarrow} \: v =27$

Final Velocity = 27 m/s

Therefore, the new velocity of the taxi is 27 m/s.

Answer 2

Given : Initial Velocity [ u ] of taxi is 15 m/s , Acceleration [ a ] of taxi is 3 m/s² & Total Time taken [ t ] is 4 second .

Exigency To Find : The final velocity [ v ] of taxi .

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀Given that ,

⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀⠀Initial Velocity [ u ] of taxi is 15 m/s ,

⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀ Acceleration [ a ] of taxi is 3 m/s² &

⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀Total Time taken [ t ] is 4 second

⠀⠀⠀⠀⠀⠀⠀⠀Finding Final Velocity  of taxi :

$\dag\:\:\sf{ As,\:We\:know\:that\::}\\\\ \qquad \bigstar \:\: \bf Acceleration \: : \: \sf The \: rate \:of \: of \: change \:of\: velocity\:is \:known \: as \: Acceleration \:. \:\\\\ \qquad\maltese\:\:\bf Formula \:for \: Acceleration\::$

$\qquad \dag\:\:\bigg\lgroup \sf{ Acceleration \:(\: a\:)\:: \dfrac { v - u}{t} }\bigg\rgroup$

⠀⠀⠀Here , v is the final velocity , u is the Initial velocity , t is the total time taken and a is the Acceleration.

$\qquad \dashrightarrow \sf Acceleration \:= \dfrac { v - u}{t}$

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad \dashrightarrow \sf Acceleration \:= \dfrac { v - u}{t}$

$\qquad \dashrightarrow \sf 3\:= \dfrac { v - 15}{4}$

$\qquad \dashrightarrow \sf 3 \times 4 \:= v - 15$

$\qquad \dashrightarrow \sf 12 \:= v - 15$

$\qquad \dashrightarrow \sf 12 + 15 \:= v$

$\qquad \dashrightarrow \sf 27 \:= v$

$\qquad \dashrightarrow \pmb{\underline{\purple{\:v = 27 \: m/s }} }\:\:\bigstar$

⠀⠀⠀⠀⠀⠀⠀⠀▪︎⠀Here , v denotes final velocity which is 27 m/s .

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Hence,\:The\:new\:velocity \:of\:taxi \:is\:\bf{27\:m/s }}.}}$