Question

7. A tent is in a shape of cylinder surmounted by conical tent. if the height and diameter is 2.1 and 4m respectively and the slant height of the top is 2.8m. Find the area of canvas making the tent. also find the cost of canvas of the tent at the rate of Rs. 500 per m^2.​

Answer 1

Answer:

• It will cost Rs.22000 for making such a tent.

Given:

• Height of Cylinderal part = 2.1m
• Diameter of Cylinderal part = 4m
• Radius of Cylinderal part = 2m
• Slant Height of Conical part = 2.8m

To Find:

• Find the area of canvas making the tent. also find the cost of canvas of the tent at the rate of Rs. 500 per m²

Solution:

CSA of Conical part + CSA of cylindrical part = Area of the canvas

➠ πrl + 2πrh

➠ π × 2 × 2.8 × 2π × 2 × 2.1

➠ 2π (2.8 + 2 × 2.1)

➠ 2π (2.8 + 4.2)

➠ 2 × 22/7 × 7

➠ 44m²

Area of canvas used for making the tent is 44 m²

Now, Cost of canvas of tent

• Cost of 1m² tent = Rs.500
• Cost of 44m² canvas = 44 × 500 = Rs.22000

It will cost Rs.22000 for making such a tent.

Answer 2

Answer:

I) Radius of base of cylinder , r= 2mm

Height of base of the cylinder , h=2.1 mm

So, the curve surface of the cylinder =2πrh

= 2π×2×2.1 = 4×22/7×2.1. = 26.4 m²

ii) Radius of the continental tent:

r=2m

length = 2.8m

so, curve surface of the cylinder =πrl

=22/7×2×2.8 =17.6 m²

Therefore the total area of the tent = 26.4 +17.6 =44m²

Cost of 1 s.q.m of the canvas is RS 500.

cost of 44 s.q.m of canvas ----

=44×500

= RS. 22,000