Question

7. A toy is made in the shape of a cylinder with one hemisphere stuck to one end
and a cone to the other end, as shown in the figure, the length of the cylindrical
part of the toy is 20cm and its diameter is 10cm. If the slant height of the cone
is 13cm. Find the surface area of the toy
13cm
10cm
20cm​

Answer 1

Answer:

T.S.A of toy = 1,303.939 cm²

Step-by-step explanation:

Cylinder: height = 20cm

radius = 5cm

Cone: slant height (l) = 13cm

radius = 5cm

Hemisphere: radius = 5cm

T.S.A. of Cylinder =

$2\pi \: r(h + r)$

= 2× 22/7 × 5 (20+5)

= 44/7 × 5 × 25

= 6.285 × 125

= 785.625 cm²

T.S.A. of Cone =

$\pi \: r \: (l + r)$

= 22/7 × 5 (13+5)

= 22/7 × 5 × 18

= 3.14 × 90

= 282.6 cm²

T.S.A. of Hemisphere =

$3\pi \: {r}^{2}$

= 3 × 22/7 × 5 × 5

= 66/7 × 25

= 9.428 × 25

= 235.714 cm²

T.S.A. of Toy = T.S.A. of Cylinder + T.S.A. of Cone + T.S.A. of Hemisphere

= 785.625 + 282.6 + 235.714

= 1,303.939 cm²

* So the T.S.A. of Toy is 1,303.939 cm²

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