Question

7.A tree is broken at a height of 5 m from the ground and its top touches the ground at a
distance of 12 m from the base of the tree. Find the original height of the tree.?
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Answer 1

Let A’CB be the tree before it broken at the point C and let the top A’ touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B.

AB = 12 m and BC = 5 m

Using Pythagoras theorem,

In ΔABC

(AC)²=(AB)²+(BC)²

(AC)²=(12)²+(5)²

(AC)²=144+25

(AC)²=169

AC = √169

AC= 13 m

Hence, the total height of the tree(A’B) = A’C + CB = 13 + 5 = 18 m.

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Hope this will help you...

Answer 2

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC, then,