Question

7. A triangle ABC is right angled at B; find the value of
sec A sin C-tan A tan C/sin B​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

sinA = BC/AC

sin C= AB/AC

tan A= BC/ AB

tan C= AB/ BC

Step-by-step explanation:

you can put these to get your answer

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