Physics, asked by sithuupulwila, 6 hours ago

7. A uniform chain of length 8.00 m initially lies stretched out on a horizontal table. (a) Assuming the coefficient of static friction between chain and table is 0.600, show that the chain will begin to slide off the table if at least 3.00 m of it hangs over the edge of the table. (b) Determine the speed of the chain as its last link leaves the table, given that the coefficient of kinetic friction between the chain and the table is 0.400.

Answers

Answered by ay5740128
1

Answer:

A uniform chain of length

l

is placed on a rough table, with its length

n

l

(n>1) hanging over the edge of the table. If the chain just begins to slide off the table by itself, the coefficient of friction between the chain and the table is:

Answered by adventureisland
1

The chain will begin to slide if x\geq 3.

Explanation:

uniform chain of length =8m

coefficient of static friction  between chain and table =-6

The chain that the chain will be begin to slide of the table if at least 3m of it hangs over the edge of the table.

Total mass of chain m=linear mass density=\frac{m}{l} =\frac{m}{8}

m_{x}=\frac{xm}{8}

This will not tall until f\leq m_{x}9

if,f\geq m_{x}9,chain will tall for least value,

uN_{1}=m*g

(.6)(m_{8}-x)g=m_{x}g

(.6)[\frac{(8-x)m}{8}]=\frac{xH}{8}

4.8-.6x=x

1.7x=4.8

x\geq 3.

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