Math, asked by shashikumar8425, 4 months ago


7. A water reservoir is 22 m long, 16 m broad and 10 m high. Find the cost of cementing its floor and the four
walls at the rate of 19 per m2

Answers

Answered by devindersaroha43
1

Answer:

Step-by-step explanation:

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3

Brainly User

Length = 4 m

Breadth = 3.5 m

Height = 3 m

Now,

= length × breadth

= 4m × 3.5 m

= 14 m²

Now,

= 2( l + b )h

= 2(4m + 3.5m) × 3

= 2 × 7.5 × 3

= 45 m²

Now,

= N1 + N2

= 14 m² + 45 m²

= 59 m²

Therefore

= 100 × 59

= 5900

Answered by Anonymous
12

Answer:

Given

Length = 22m

breadth = 16 m

height= 10 m

Area of floor = l × b

= 22×16

= 352 m²

Area of 1st wall of pool = l×h

= 22× 10

= 220m²

Area of [2nd wall ] opposite wall = Area of 1st wall = 220m²

Area of 3rd wall = b× h

= 16×10

= 160m²

Area of [ 4th wall ] opposite wall = area of 3rd wall = 160m²

Total area = (352+220+220+160+160)m²

= 1,112m²

Cost if 1m² = Rs.19

1112m² cost = 19×1112

= Rs. 21,128

Step-by-step explanation:

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